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Biology, 26.02.2020 13:10, aswinkumarmishra

Explain the polarisation of the membrane of a nerve fibre

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The correct answer was given: sandhu2840
answer (a) Polarisation of the membrane of a nerve fibre

During resting condition, the concentration of K+ ions is more inside the axoplasm while the concentration of Na+ ions is more outside the axoplasm. As a result, the potassium ions move faster from inside to outside as compared to sodium ions. Therefore, the membrane becomes positively charged outside and negatively charged inside. This is known as polarization of membrane or polarized nerve.

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The correct answer was given: M015
(a) Polarisation of the membrane of a nerve fibre

During resting condition, the concentration of K+ ions is more inside the axoplasm while the concentration of Na+ ions is more outside the axoplasm. As a result, the potassium ions move faster from inside to outside as compared to sodium ions. Therefore, the membrane becomes positively charged outside and negatively charged inside. This is known as polarization of membrane or polarized nerve.



(b) Depolarisation of the membrane of a nerve fibre

When an electrical stimulus is given to a nerve fibre, an action potential is generated. The membrane becomes permeable to sodium ions than to potassium ions. This results into positive charge inside and negative charge outside the nerve fibre. Hence, the membrane is said to be depolarized.



(c) Conduction of a nerve impulse along a nerve fibre

There are two types of nerve fibres – myelinated and non-myelinated. In myelinated nerve fibre, the action potential is conducted from node to node in jumping manner. This is because the myelinated nerve fibre is coated with myelin sheath. The myelin sheath is impermeable to ions. As a result, the ionic exchange and depolarisation of nerve fibre is not possible along the whole length of nerve fibre. It takes place only at some point, known as nodes of Ranvier, whereas in non-myelinated nerve fibre, the ionic exchange and depolarization of nerve fibre takes place along the whole length of the nerve fibre. Because of this ionic exchange, the depolarized area becomes repolarised and the next polarized area becomes depolarized.

(d) Transmission of a nerve impulse across a chemical synapse

Synapse is a small gap that occurs between the last portion of the axon of one neuron and the dendrite of next neuron. When an impulse reaches at the end plate of axon, vesicles consisting of chemical substance or neurotransmitter, such as acetylcholine, fuse with the plasma membrane. This chemical moves across the cleft and attaches to chemo-receptors present on the membrane of the dendrite of next neuron. This binding of chemical with chemo-receptors leads to the depolarization of membrane and generates a nerve impulse across nerve fibre.

The chemical, acetylcholine, is inactivated by enzyme acetylcholinestrase. The enzyme is present in the post synaptic membrane of the dendrite.

It hydrolyses acetylcholine and this allows the membrane to repolarise
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The correct answer was given: akshat8712

Polarisation of the membrane of a nerve fibre

During resting condition, the concentration of K+ ions is more inside the axoplasm while the concentration of Na+ ions is more outside the axoplasm. As a result, the potassium ions move faster from inside to outside as compared to sodium ions. Therefore, the membrane becomes positively charged outside and negatively charged inside. This is known as polarisation of membrane or polarised nerve.

Answer
The correct answer was given: chennupatitanuja

(b) Depolarisation of the membrane of a nerve fibre. ... When an electrical stimulus is given to a nerve fibre, an action potential is generated. The membrane becomes permeable to sodium ions than to potassium ions. This results into positive charge inside and negative charge outside the nerve fibre.

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The correct answer was given: yachna18

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Explanation:

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Explain the following processes: (a) polarisation of the membrane of a nerve fibre(b) depolarisation
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The correct answer was given: atharvakarawade1

Depolarisation of the membrane of a nerve fibre. ... When an electrical stimulus is given to a nerve fibre, an action potential is generated. The membrane becomes permeable to sodium ions than to potassium ions. This results into positive charge inside and negative charge outside the nerve fibre.

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Answer
The correct answer was given: lighy6155

Explanation of the Process of Depolarization of the membrane of a nerve fibre  is as follows:

A nerve fibre generates an action potential after connecting with electric stimulus. To the sodium ions, the membrane becomes permeable. The nerve fibre gets positive and negative charge inside and outside respectively. Depolarization occurs during the period of transmission of nerve. This is the process of Depolarization of membrane.
Answer
The correct answer was given: rajveer8591

Here, option A is the correct answer.

When a electrical stimulus is received by a nerve fibre a potential action gets generated.

Therefore the membrane becomes porous to the sodium ions as compared to the potassium ions.

Therefore, this gives rise to a positive amount of charge inside of the nerve fibre while the outside has negative charge.

The membrane thereby becomes depolarized.

Answer
The correct answer was given: ritikkhatana235

When an electrical stimulus is given to a nerve fibre, an action potential is generated. The membrane becomes permeable to sodium ions than to potassium ions. This results into positive charge inside and negative charge outside the nerve fibre. Hence, the membrane is said to be depolarized.

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