Explanation:plz mark as brainliest answer and thx for the brainliest answer even follow me hey dudehere is ur answer..The reactions which take place in the cell during discharge (when current is drawn from the cell) are,At anode: (oxidation)Pb + SO42–→PbSO4(s) + 2e–At cathode: (reduction)PbO2(s) + 4H++ SO42–+ 2e– → PbSO4(s) + 2H2ONet cell reaction:Pb + PbO(s) + 4H+ + 2SO42– → 2PbSO4(s) + 2H2O.thanks!
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The lead acid battery uses lead as the anode and lead dioxide as the cathode, with an acid electrolyte. During the charging process, the reactions at each electrode are reversed; the anode becomes the cathode and the cathode becomes the anode.
Cell reaction during charging phase= 2PbSO4 + 2H2O = Pb + PbO2 + 4H+ 2SO4²-
HERE IS YOUR ANSWER,
⇒ A lead storage battery is an example of SECONDARY CELL.
NOW, THE REACTIONS AT ANODE AND CATHODE ARE :
⇔ AT ANODE,
⇒ Pb (s) + SO₄ → PbSO₄ (s) + 2e⁻
⇔ AT CATHODE,
⇒ PbO₂ (s) + 4H⁺ + SO₄²⁻ + 2e⁻ → PbSO₄ (s) + 2H₂O.
HOPE IT HELPS YOU,
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