Sinx/1+cos²xdx with upper limit π/2 and lower limit 0​

π / 4

Step-by-step explanation:

Solution----->

1) Plzzz see the attachmet

2) To solve the intregation , we apply a substitution which is as follows ,

Let , Cosx = t

Differentiating with respect to x , we get,

=> - Sinx dx = dt

=> Sinx dx = - dt

Then we find new limits

If , x = 0 , t = Cos0 = 1

If , x = π / 2 , t = Cos π/2 = 0

So lower limit is 1 and upper limit is 0

3) We know that,

∫ dx / ( 1 + x² ) = tan⁻¹ x + C

Applying it and putting limits we get, answer

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Explanation:

In physics, a force is any interaction that, when unopposed, will change the motion of an object. A force can cause an object with mass to change its velocity, i.e., to accelerate. Force can also be described intuitively as a push or a pull. A force has both magnitude and direction, making it a vector quantity

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Explanation:

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Explanation:

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Explanation:

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final velocity of A = (M1 - M2/M1+M2)*initial velocity of A

so, vel. of A = (1-2/1+2)*20 = -20/3 m/s

vel. of B = (2M1/M1+M2)*initial velocity of B

so,vel. of B = (2*1/2+1)*(-10)= -20/3 m/s

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