Top surface of a table is a trapezium in shape as shown in the figure alongside find its area its if its parallel sides are 1.5 and 2 metre and the perpendicular distance between them is 1.2.
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answer:

answer:

The any tells the cricket to “dance the winter way”. Do you link the word

‘dance’ is appropriate here ? if so, way?

Angle

Area of trapezium=(

2

a+b

)×h

h=1.2m; a=2m; b=1.5m

(

2

2+1.5

)×1.2=2.1m

2

first take the AP as 15 CM as using so ABB is 15 CM of total and then then the find the value of a tree by the sum of example of the theorem formula cause this is equal to this I can't expensive and then this is equals to this then AP equals to

let the highest mark be ×

the lowest mark of a class be y

condition 1

highest mark is 3 more than 3times the lowest

i.e x=3+3y

x-3y=3. (equation 1)

condition2

if highest mark is 96

i.e x=96

finf y

therefore put x=96 in equantion 1

x-3y=3

96-3y=3

96-3=3y

93=3y

93/3=y

31=y

ans- if highest mark is 96 then lowest mark is 31

2)

let the term added to get ans -4b+2c be x

therefore

x=(-4b+2c)-{(3a+2b+40)+(2b-3c+a)}

x=(-4b+2c)-{3a+2b+40+2b-3c+a}

x=(-4b+2c)-{3a+a+2b+2b+40-3c}

x=(-4b+2c)-{4a+4b+40-3c}

x=-4b+2c-4a-4b-40+3c

x=-8b+5c-4a-40

ans-. -8b+5c-4a-40 this term should be added to get ans -4b+2c

We know that ∠BCD and ∠ABC are alternate interior angles

∠BCD=∠ABC=25

o

We know that the angle subtended by an arc of a circle at the center is double the angle subtended by the arc at any point on the circumference

∠BOD=2∠BCD

It is given that ∠BCD=25

o

So we get

∠BOD=2(25

o

)

By multiplication

∠BOD=50

o

In the same way

∠AOC=2∠ABC

So we get

∠AOC=50

o

From the figure, we know that AB is a straight line passing through the centre

Using the angle sum property

∠AOC+∠COD+∠BOD=180

o

By substituting the values

50

o

+∠COD+50

o

=180

o

On further calculation

∠COD+100

o

=180

o

By subtraction

∠COD=180

o

−100

o

so we get

∠COD=48

o

We know that

∠CED=

2

1

∠COD

So we get

∠CED=

2

80

o

By division

∠CED=40

o

Therefore, ∠CED=40

o