If sin (A-B)=1/2,cos(A-B)=1/2 find A and B

Hello!

Step-by-step explanation:

sin (a+b) = 1

=> sin (a+b) = sin 90degree

=> a+b = 90 degree(1)

Again, cos(a-b) = 1/2

=> cos (a-b) = cos 60degree

=> a-b = 60 degree(2)

Now, (1)-(2),we get_

a+b - (a-b) = 90-60

=> a + b - a + b = 30 degree

=> 2b = 30 degree

=> b = 30degree / 2

=> b = 15 degree.

Again putting 'b' in equation (1), we get_

a + b = 90 degree

=> a + 15 = 90 degree

=> a = 90-15 degree

=> a = 75 degree

THEREFORE , a = 75 degree & b = 15 degree.

THANK YOU forthe question. Hope this would be useful to you!

Hi

The solution is given in the attachment below

Please do refer to it

Hope it helps you

Please mark it the brainliest if you are satisfied with the solution given

Have a good day

nhi pata Google kar lo bhai

sin(a-b)=30 sin 30=1/2

cos(a+b)=60

by solving

2a=90

a=90/2

a=45

b=15