Math, 26.02.2020 09:10, mohit81281

Find the least number when divided by 6 7 8 9 and 12 leave the same remainder 2 in case

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The correct answer was given: sandhu2840

For finding the least no. we have to multiply all these no. first

therefore , 6 x 7 x 8 x 9 x 12

= 36288

now we want two as a remainder this means if we will divide by any of these no. then 2 will remain therefore we have to add 2 in the product of all these no.

36288 + 2 = 36290

hope it helps

please mark it as brainliest ans.

The correct answer was given: riddhima95

2521 . because l.c.m. of 6,7,8 9,10, is 2520. so required number is 2520+1 = 2521.

The correct answer was given: priyansh86

504 is the least number exactly divisible by 6,7,8,9 and 12. Hence, least number which when divided by 6,7,8,9 and 12 leaves remainder 2 in each case=504+2=506.

The correct answer was given: Vsinghvi

6=2*3

7=1*7

8=2*2*2

9=3*3

10=2*5

So, the L.C.M of 6,7,8,9 and 10 is = (2*2*2*3*3*7)

= 504

So, the number is (504+1)

= 505

The correct answer was given: vanshsingh15

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The correct answer was given: BTanisha

Lcm of (6,7,8,9,12) =504

Remainder is 1

So Number is in the format of 504K+1

Let K be 1

= 504 (1) +1

= 505

Or one could evem say that let K be 0

= 504 (0)+1

= 1

The correct answer was given: akshat8712

Step-by-step explanation:

I dont know sorry ohohohoh

The correct answer was given: ridhima37

Taking the LCM of 6,7,8,9,12 we got 168

so to make it a number leaving 1 as a remainder we will add 1 to 168 making it 169

So 169 is the number req.

Step-by-step explanation:

The correct answer was given: shashidarshanbiradar

Find LCM ( 6,7,8,9,10 ) = 7560 which is divisible by all given digits. So, when we add 1 to 7560 and divided by given digits leaves remainder 1 .
i.e., 7560 + 1 = 7561 is the number which when divided by (6,7,8,9,10) leaves remainder 1.

The correct answer was given: deepakyadav5930

Given numbers,
6 , 7 , 8, 9 and 12
Prime factorization of,
6=2×3
7=1×7
8=2³
9=3²
12=2²×3
LCM=product of each prime factor of highest power
LCM=2³×3²×7=504
504 is the least number exactly divisible by 6,7,8,9 and 12.

Hence,
least number which when divided by 6,7,8,9 and 12 leaves remainder 2 in each case=504+2=506.