Find a positive number when increased by 17 is equal to 60 times the reciprocal of the number 1 2 2 3 3 5 4 6

the answer is 3

Step-by-step explanation:

If the number is x,

then ,x+17=60/x

x2+17x-60=0

(X+20)(x-3)=0

X=3,-20, so x=3(as 3 is positive)

3

Step-by-step explanation:

Let the number be x

x + 17  = 60 * 1/x = 60/x

x * (x+17) = 60

x² + 17x - 60 = 0

(x+20)(x -3) = 0

x+20 = 0      or x-3 = 0

x = (-20) or x = 3

x is a positive number. so  x = 3

If the number is x,

Then, x + 17 =60/x

x2 + 17x - 60 = 0

(x + 20)(x - 3) = 0

x = 3, -20, so x = 3 (as 3 is positive)

Let the positive number be x.

Given that A number when increased by 17 is equal to 60 times the reciprocal of the number.

= > x + 17 = (60/x).

= > x(x + 17) = 60

= > x^2 + 17x = 60

= > x^2 + 17x - 60 = 0

= > x^2 - 3x + 20x - 60 = 0

= > x(x - 3) + 20(x - 3) = 0

= > (x - 3)(x + 20) = 0

= > x = 3, -20[Neglect negative values]

= > x = 3.

Therefore, the positive number is 3.

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Step-by-step explanation:

Let the positive number be x, then it's reciprocal will be 1/x.

According to the question, equation formed is:

x + 17 = 60 (1/x)

x + 17 = 60/x

Taking x from RHS to LHS ,

x^2 + 17x = 60

This can be written as,

x^2 + 17x - 60 = 0

x^2 + 20x - 3x - 60 = 0

x (x + 20) - 3 (x + 20) = 0

(x - 3) (x + 20) = 0

So,

x - 3 = 0 OR x + 20 = 0

Hence, x = 3. OR. x = -20

As x is positive, x is 3.

Hence, x = 3