Explanation:plz mark as brainliest answer , follow me and thx for the brilliant questionGiven=R1=R2=2ohmsInternal resistance=rIn parallel current flows=1.2 AIn series current flows =0.4AAssuming potential of source remains constant in both case:Equivalent resistant in parallel :Rp=R1R2/R1+R2=2x2/2+2=1ohmThus , sum of potential drops at individual resistance=total potential difference appliedi(Rp+r)=v1.2(1+r)=V1now for series connection:Rs=2+2+r=r+4Thus sum of potential drops at individual resistance=total potential difference appliediRs=V0.4x(4+r)=V2from eq. 1 and 21.2(1+r)=0.4x(4+r)r=0.5ohms
a 1.2 * 2= x*0.4
x= 6 is my ans..
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if the projections of a line segment on the x,y and z axes in 3-dimensional space are 2,3 and 6 respectively, then the length of line segment is
common electric bulb is known as incandescent bulb where a filament is heated to a very temperature to emit light through a process called black body radiation. heat is generated due to resistivity when electricity is passed through an object. a hot object constantly emits electromagnetic radiation.follow ❤