7.1*10raise to the power19 electron
I=200*10raise to the power-3=0.2A
ne=12/1.67*10raise to the power-19
ans: ne=7.1*10raise to the power19 electron
Current is the amount of charge passing through a conducted in a particular interval of time
A current of 200 mA is flowing through the lamp. One ampere is the current that flows through the lamp when one coulomb of charge passes in one second. The charge of an electron is 1.602*10^-19 C.
The number of electrons that pass through the lamp in one second is equal to (200*10^-3)/(1.602*10^-19) . The number of electrons that pass through the lamp in one minute is equal to (200*10^-3*60)/(1.602*10^-19) = 7.49*10^19 .
Another way of determining this is to use the fact that one ampere is current that flows when 6.241*10^18 electrons pass through in one second. This gives the number of electrons passing through the lamp in a minute as 6.241*10^18*60 = 7.48*10^19
Inorder to solve the question
Use the equation
220*1/10³*60s=No of coulomb
Since one of coulomb of charge has 6.25*10¹⁸ electrons
Then 1.32coulomb will have
Hope it helps
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Q = It
= 200 * 10-³ * 60
= 12 As
Q = ne
n = Q/e
The answer of question attach in figure.
Explanation:Infinity many electrons can pass in a lamp .
Explanation:Here, current I = 300 mA = 0.3 A
time t = 1 minute = 60 seconds
Now, charge Q = I x t = 0.3 x 60 = 18 coulomb
and no. of electrons = (total charge)/(charge on 1 electron)
? no. of electrons = (18)/(1.6 x 10-19)
= 1.125 x 1020 electrons